Answer
100
Work Step by Step
To find 5C2 and 5C3, we plug 5 and 3 or 5 and 2 into the combination formula $\frac{n!}{r!(n-r)!}$. From there we get $\frac{5!}{2!(3)!}$ for both 5c2 and 5c3. We solve to get 10 for both. Multiply 10 and 10 to get 100.
