Answer
$(x-4)^2=-4(y+1)$
Work Step by Step
Vertex: $V(h,k)=V(4,-1)$
$h=4$
$k=-1$
Equation of a parabola with vertical axis and vertex at $(h,k)$:
$(x-h)^2=4p(y-k)$
$(x-4)^2=4p(y+1)$
Use the point $(6,-2)$:
$(6-4)^2=4p(-2+1)$
$4=-4p$
$p=-1$
Finally:
$(x-4)^2=-4(y+1)$
