Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.4 - Shifted Conics - 11.4 Exercises - Page 815: 39

Answer

$(x+3)^{2} = 12 (y-5)$

Work Step by Step

General Equation of a Parabola: $(x-h)^{2} = 4p (y-k)$ Vertex is at (-3, 5), so h = -3 and k = 5 Directrix is at y=2 Thus p (distance from vertex to directrix) is equal to 3 So the equation is $(x+3)^{2} = 12 (y-5)$
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