Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.4 - Shifted Conics - 11.4 Exercises - Page 815: 33

Answer

$(y-1)^2-x^2=1$

Work Step by Step

Step 1. Based on the shape and orientation of the curve, we can assume the equation as $\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1$ Step 2. Identify the center as $(0,1)$ from the figure given in the Exercise, thus $h=0, k=1$ Step 3. Identify the vertices as $(0,2)$ and $(0,0)$, so we have $2a=2$ and $a=1$ Step 4. With the given asymptote: $y=x+1$, we have $\frac{a}{b}=1$ and $b=a=1$ Step 5. Conclusion: the equation for the given curve is $(y-1)^2-x^2=1$
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