Answer
$(y-3)^{2} = 4(x-2)$
Work Step by Step
General Equation of a Parabola: $(y-k)^{2} = 4p (x-h)$
(Directrix is a vertical line, so it is a $y^{2} = x$ general function)
Focus is at (1,3), Directrix is x=3
Vertex is half the distance between the focus and directrix, so x (of vertex) = (1+3)/2 = (2, 3)
p is distance from vertex to focus, so that is equal to 1
Thus the equation is $(y-3)^{2} = 4(x-2)$
