Answer
a)$3a\sqrt a+\sqrt a$
b)$4\sqrt x+x^2\sqrt x$
Work Step by Step
a)$\sqrt {9a^3}+\sqrt a=\sqrt {9a^2}\sqrt a+\sqrt a=3a\sqrt a+\sqrt a$
b)$\sqrt {16x}+\sqrt {x^5}=4\sqrt x+\sqrt {(x^2)^2}\sqrt x=4\sqrt x+x^2\sqrt x$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 51
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