Answer
a) $\frac{x^7}{y}$
b) $\frac{a^9}{8b^6}$
Work Step by Step
a) $\frac{x^2y^{-1}}{x^-5}$ = $\frac{x^{2+5}}{y}$ = $\frac{x^7}{y}$
b) $(\frac{a^3}{2b^2})^3$ = $\frac{a^{(3)(3)}}{2^3b^{(2)(3)}}$ =$\frac{a^9}{8b^6}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 37
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