Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 35

Answer

a) 6$x^3$$y^5$ b) $\frac{25w^4}{z}$

Work Step by Step

a) (3$x^3$$y^2$)(2$y^3$) = (2)(3)$x^3$$y^{2+3}$ = 6$x^3$$y^{5}$ b) $(5$$w^2$$z^{-2}$)$^{2}$($z^3$) = $5^2$$w^{(2)(2)}$$z^{(-2)(2)}$$z^3$ = 25$w^4$$z^{-4+3}$ = 25$w^4$$z^{-1}$ = $\frac{25w^4}{z}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.