Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 26

Answer

a) $8\sqrt 5$ b)$3$ c)$5$ $\sqrt[3] 9$

Work Step by Step

a)$\sqrt 10\sqrt {32}=\sqrt {10\times32}=\sqrt {320}=\sqrt {64}\times\sqrt 5=8\sqrt 5$ b)$\frac{\sqrt {54}}{\sqrt 6}=\sqrt 9=3$ c) $\sqrt[3] 15$ $\sqrt[3] 75$ $=$ $\sqrt[3]5\times3\times\times5\times5\times3$ $=$ $\sqrt[3]5\times5\times\times5\times3\times3$ = $5$ $\sqrt[3] 9$
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