Answer
a) $\frac{1}{2}$
b) $\frac{1}{8}$
c) $\frac{9}{4}$
Work Step by Step
a) $(\frac{5}{3})^{0}$ $\times$ $2^{-1}$= 1 $\times$ $2^{-1}$ = $\frac{1}{2}$.
Note that anything to the power 0 is equal to 1
b) $\frac{2^{-3}}{3^{0}}$= $2^{-3}$= $\frac{1}{2^{3}}$ = $\frac{1}{8}$
c) ($\frac{2}{3}$)$^{-2}$ = $\frac{1}{\frac{4}{9}}$ = $\frac{9}{4}$
