Answer
See below.
Work Step by Step
$LHS=ln|1+cos\theta|+ln|1-cos\theta|=ln|(1+cos\theta)(1-cos\theta)|=ln|1-cos^2\theta|=ln|sin^2\theta|=2ln|sin\theta|=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 498: 99
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
