Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 498: 115

Answer

$sin\theta =\frac{5}{13}$, $cos\theta =-\frac{12}{13}$, $tan\theta =-\frac{5}{12}$, $cot\theta =-\frac{12}{5}$, $sec\theta =-\frac{13}{12}$, $csc\theta =\frac{13}{5}$.

Work Step by Step

Given $x=-12,y=5$, we have $r=\sqrt {(-12)^2+5^2}=13$. Thus $sin\theta=\frac{y}{r}=\frac{5}{13}$, $cos\theta=\frac{x}{r}=-\frac{12}{13}$, $tan\theta=\frac{y}{x}=-\frac{5}{12}$, $cot\theta=\frac{x}{y}=-\frac{12}{5}$, $sec\theta=\frac{r}{x}=\frac{13}{12}$, $csc\theta=\frac{r}{y}=-\frac{13}{5}$.
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