Answer
See below.
Work Step by Step
1. $f(x)=sin(x)\cdot tan(x)=sin(x)(\frac{sin(x)}{cos(x)})=\frac{sin^2(x)}{cos(x)}$
2. $g(x)=sec(x)-cos(x)=\frac{1}{cos(x)}-cos(x)=\frac{1-cos^2(x)}{cos(x)}=\frac{sin^2(x)}{cos(x)}$
3. Thus $f(x)=g(x)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 498: 101
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