Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 498: 93

Answer

See below.

Work Step by Step

$LHS=\frac{tan\alpha+tan\beta}{cot\alpha+cot\beta} =\frac{tan\alpha+tan\beta}{cot\alpha+cot\beta}\times\frac{tan\alpha tan\beta}{tan\alpha tan\beta} =\frac{(tan\alpha+tan\beta)tan\alpha tan\beta}{tan\beta+tan\alpha} =tan\alpha\ tan\beta=RHS$
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