Answer
See below.
Work Step by Step
$LHS=(tan\alpha+tan\beta)(1-cot\alpha cot\beta)+(cot\alpha+cot\beta)(1-tan\alpha tan\beta)
=tan\alpha+tan\beta-cot\beta-cot\alpha+cot\alpha+cot\beta- tan\beta-tan\alpha =0=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 498: 94
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