Answer
$0.46$
Work Step by Step
Let $\theta = \cot^{-1} {2} \hspace{20pt} \therefore \cot{\theta} = 2$
Since $\tan{\theta}= \dfrac{1}{\cot{\theta}}$, then
$\tan{\theta} = \dfrac{1}{2}$
Thus,
$\theta = \tan^{-1} {\left(\frac{1}{2}\right)}\approx 0.46$
Hence.
$\cot^{-1} {2}= \tan^{-1} {\left(\frac{1}{2}\right)} \approx \boxed{0.46}$