Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.2 The Inverse Trigonometric Functions (Continued) - 6.2 Assess Your Understanding - Page 480: 47



Work Step by Step

Let $\theta = \cot^{-1} {2} \hspace{20pt} \therefore \cot{\theta} = 2$ Since $\tan{\theta}= \dfrac{1}{\cot{\theta}}$, then $\tan{\theta} = \dfrac{1}{2}$ Thus, $\theta = \tan^{-1} {\left(\frac{1}{2}\right)}\approx 0.46$ Hence. $\cot^{-1} {2}= \tan^{-1} {\left(\frac{1}{2}\right)} \approx \boxed{0.46}$
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