Answer
$\sqrt 2$
Work Step by Step
The range of $\tan^{-1}{x}$ is $[-\dfrac{\pi}{2},\dfrac{\pi}{2}]$.
Here, $\tan^{-1}(1)=\dfrac{\pi}{4}$, because $\tan{(\dfrac{\pi}{4})}=1$ and $\dfrac{\pi}{4}$ lies in the range of $\tan^{-1}{x}$ .
Therefore, we have:
$\csc [\tan^{-1}(1)]=\csc ({\dfrac{\pi}{4}})=\sqrt 2$