Answer
$\dfrac{2 \pi}{3}$
Work Step by Step
We know that the trigonometric function $\sec^{-1} x$ has range: $[0, \dfrac{\pi}{2} ) \cup ( \dfrac{\pi}{2}, \pi]$.
Here, $\sec^{-1} (-2)=\dfrac{2 \pi}{ 3}$, because $\sec(\dfrac{2\pi}{3})=-2$ and $\dfrac{2 \pi}{3}$ lies in the range of $\sec^{-1}{x}$ .