Answer
$x=sec(y)$, $\ge1$, $0,\pi$
Work Step by Step
Based on the definition of inverse secant function, $y=sec^{-1}x$ means $x=sec(y)$, where $|x|\ge1$ and $0\le y\le\pi$ where $y\ne\frac{\pi}{2}$.
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.