Answer
$\frac{2\pm i\sqrt {2}}{2}$
See graph.
Work Step by Step
Step 1. $-2x^2+4x-3=0 \Longrightarrow x=\frac{-4\pm\sqrt {16-4(-2)(-3)}}{2(-2)}=\frac{2\pm i\sqrt {2}}{2}$
Step 2. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 186: 36
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