Answer
$y=-3(x-2)^2-4$
Work Step by Step
Based on the given conditions, we can write a general form as $y=a(x-h)^2+k$, with $h=2, k=-4$, we have $y=a(x-2)^2-4$. Let $x=0$, we have the y-intercept $y=4a-4=-16$ and $a=-3$. Thus $y=-3(x-2)^2-4$
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