Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 186: 30

Answer

$y=-3(x-2)^2-4$

Work Step by Step

Based on the given conditions, we can write a general form as $y=a(x-h)^2+k$, with $h=2, k=-4$, we have $y=a(x-2)^2-4$. Let $x=0$, we have the y-intercept $y=4a-4=-16$ and $a=-3$. Thus $y=-3(x-2)^2-4$
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