Answer
$y=(x+1)^2+2$
Work Step by Step
Based on the given conditions, we can write a general form as $y=a(x-h)^2+k$, with $h=-1, k=2$, we have $y=a(x+1)^2+2$. With point $(1,6)$, we have $6=a(1+1)^2+2$ and $a=1$. Thus $y=(x+1)^2+2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 186: 31
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