Answer
maximum $f(2) =16$
Work Step by Step
Given $f(x)=-3x^2+12x+4$, we have $a=-3\lt0, b=12$, thus there is a maximum at $x=-\frac{b}{2a}=-\frac{12}{2(-3)}=2$ with a value $f(2)=-3(2)^2+12(2)+4=16$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 186: 29
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