Answer
minimum $f(1) =1$
Work Step by Step
Given $f(x)=3x^2-6x+4$, we have $a=3\gt0, b=-6$, thus there is a minimum at $x=-\frac{b}{2a}=-\frac{-6}{2(3)}=1$ with a value $f(1)=3(1)^2-6(1)+4=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 186: 27
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