Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Chapter Review - Review Exercises - Page 186: 32

Answer

$ (-8,2) $

Work Step by Step

Step 1. $x^2+6x-16\lt0 \Longrightarrow (x+8)(x-2)\lt0$ Step 2. Identify boundary points $x=-8,2$ and form intervals $(-\infty,-8),(-8,2),(2,\infty)$ Step 3. Choose test values $x=-9,0,3$, test the inequality to get results $False,\ True,\ False$. Step 4. Thus we have the solution $ (-8,2) $
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