Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.2 Algebra Techniques for Finding Limits - 13.2 Assess Your Understanding - Page 903: 60

Answer

$x^4+8x^3+24x^2+32x+16$

Work Step by Step

Based on the Binomial Theorem, we have $(x+2)^4=x^4+4(2)x^3+6(2)^2x^2+4(2)^3x+(2)^4 =x^4+8x^3+24x^2+32x+16$
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