Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.2 Algebra Techniques for Finding Limits - 13.2 Assess Your Understanding - Page 903: 49

Answer

$0$

Work Step by Step

The general formula for average rate of change from $a$ to $b$ can be written as: $\dfrac{f(b)-f(a)}{b-a}$ Here, we have: $f(x)=3x^3-2x^2+4$ Thus, we find the average rate of change as: $\lim\limits_{x\to 0}\dfrac{f(x)-f(0)}{x-0}=\lim\limits_{x\to -1}\dfrac{(3x^3-2x^2+4)-[3(0)^3-2(0)^2+4]}{x} \\=\lim\limits_{x\to 0}\dfrac{x(3x^2-2x)}{x}$ In order to simplify the above expression, we will use the following rules. $(a) \lim\limits_{x \to a} \dfrac{p(x)}{q(x)}=\dfrac{\lim\limits_{x \to a} p(x)}{\lim\limits_{x \to a} q(x)} \\ (b) \lim\limits_{x \to a} k(x)=k(a)$ ; where $a$ is a constant. $\lim\limits_{x\to 0} (3x^2-2x) \\=(3)(0)^2-2(0) \\=0 $
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