## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$8$
We know that $\lim\limits_{x \to a} k(x)=k(a)$, where $a$ as a constant. Thus, we have: $\lim\limits_{x \to 1} (x^2+1)^3=(1^2+1)^3 \\=(1+1)^3 \\=2^3 \\=8$