Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.2 Algebra Techniques for Finding Limits - 13.2 Assess Your Understanding - Page 903: 21



Work Step by Step

We know that $\lim\limits_{x \to a} k(x)=k(a)$, where $a$ as a constant. Thus, we have: $\lim\limits_{x \to 1} (x^2+1)^3=(1^2+1)^3 \\=(1+1)^3 \\=2^3 \\=8$
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