Answer
$8$
Work Step by Step
Use the limit properties:
$(1) \lim\limits_{x \to a} (px \pm qx)=\lim\limits_{x \to a} p(x) \pm \lim\limits_{x \to a} qx \\ (2) \ \lim\limits_{x \to a} l(x)=l (a) $
where $a$ is a constant.
$\lim\limits_{x \to -1} (3x^2-5x) =\lim\limits_{x \to -1}(3x^2) -\lim\limits_{x \to -1} (5x) \\=3(-1)^2-5(-1)\\ =3+5 \\=3-(-5)\\=8$
