Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.2 Algebra Techniques for Finding Limits - 13.2 Assess Your Understanding - Page 903: 28

Answer

$-1$

Work Step by Step

In order to simplify the given expression, we will use the following rules: (a) $\lim\limits_{x \to a} [k(x)]^n =[\lim\limits_{x \to a} k(x)]^n$ (b) $\lim\limits_{x \to a} k(x)=k(a)$ where $a$ is a constant. --- Thus, we have: $\lim\limits_{x \to -1} (2x+1)^{5/3}=[\lim\limits_{x \to -1} [(2x+1)^{5/3}] \\ =[(2)(-1)+1]^{5/3} \\ =(-1)^{5/3} \\ =-1$
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