## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$8$
Use the limit properties: $(1) \ \lim\limits_{x \to a} l(x)=l (a) \\ (2) \lim\limits_{x \to a} (px+q)=\lim\limits_{x \to a} p(x)+ \lim\limits_{x \to a} q$ where $a$ is a constant. $\lim\limits_{x \to 2} (3x+2) = \lim\limits_{x \to 2} (3x) +\lim\limits_{x \to 2} (2) \\=3(2)+2\\=6+2\\=8$