Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Chapter Review - Review Exercises - Page 815: 48

Answer

See graph, bounded, $\left(2,0\right),\left(4,0\right),\left(0,1\right),\left(0,8\right)$.

Work Step by Step

See graph for $\begin{cases}x\ge0\\y\ge0 \\ 2x+y\le8\\ x+2y\ge2 \end{cases}$ It is bounded, and we can identify the corner(s) as $\left(2,0\right),\left(4,0\right),\left(0,1\right),\left(0,8\right)$.
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