Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Chapter Review - Review Exercises - Page 815: 29

Answer

$(2,-1)$

Work Step by Step

Based on the given equations, we have $D=\begin{vmatrix} 1 & -2\\ 3 & 2 \end{vmatrix}=1(2)-(-2)(3)=8$, Use the Cramer’s Rule, we have $D_x=\begin{vmatrix} 4 & -2\\ 4 & 2 \end{vmatrix}=4(2)-(4)(-2)=16$, $D_y=\begin{vmatrix} 1 & 4\\ 3 & 4 \end{vmatrix}=4(1)-(4)(3)=-8$, Thus $x=\frac{D_x}{D}=2, y=\frac{D_y}{D}=-1$ or $(2,-1)$
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