Answer
$(2,-1)$
Work Step by Step
Based on the given equations, we have $D=\begin{vmatrix} 1 & -2\\ 3 & 2 \end{vmatrix}=1(2)-(-2)(3)=8$,
Use the Cramer’s Rule, we have
$D_x=\begin{vmatrix} 4 & -2\\ 4 & 2 \end{vmatrix}=4(2)-(4)(-2)=16$,
$D_y=\begin{vmatrix} 1 & 4\\ 3 & 4 \end{vmatrix}=4(1)-(4)(3)=-8$,
Thus $x=\frac{D_x}{D}=2, y=\frac{D_y}{D}=-1$ or $(2,-1)$