Answer
$(-\frac{2}{5},-\frac{11}{5}),(-2,1)$
Work Step by Step
1. From the 1st given equation, we have $y=-2x-3$
2. Use the above in the 2nd equation to get $x^2+4x^2+12x+9=5$ or
$5x^2+12x+4=0$ or $(5x+2)(x+2)=0$, thus $x=-\frac{2}{5},-2$
3. Use the 1st equation to get $y=2, 1$
4. We have the solution(s) $(-\frac{2}{5},-\frac{11}{5}),(-2,1)$
