Answer
$(1,-1)$
Work Step by Step
1. With $y\ne0$, multiply $y$ to the 2nd equation to get $x^2-x+y^2+y=0$
2. Take the difference between the above and the 1st equation to get
$2x=2$, thus $x=1$
3. Use the 1st equation to get $1-3+y^2+y=-2$ or $y^2+y=0$, thus $y=-1$ (discard y=0)
4. We have the solution $(1,-1)$
