Answer
See graph, unbounded, $\left(0,2\right)$.
Work Step by Step
See graph for $\begin{cases} -2x+y\le2 \\ x+y\ge2 \end{cases}$
It is unbounded, and we can identify the corner(s) as $\left(0,2\right)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 10 - Systems of Equations and Inequalities - Chapter Review - Review Exercises - Page 815: 46
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