Answer
$ \frac{4-x}{(x+4)^{3/2}}$
Work Step by Step
$\frac{(x+4)^{1/2}-2x(x+4)^{-1/2}}{x+4}=\frac{(x+4)-2x}{(x+4)^{3/2}}=\frac{4-x}{(x+4)^{3/2}}$
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