Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 82

Answer

$\frac{1}{(x^2+1)^{3/2}}$

Work Step by Step

1. $\sqrt {x^2+1}-x\cdot\frac{2x}{2\sqrt {x^2+1}}=\frac{2(x^2+1)-2x^2}{2\sqrt {x^2+1}}=\frac{1}{\sqrt {x^2+1}}$ 2. $\frac{\sqrt {x^2+1}-x\cdot\frac{2x}{2\sqrt {x^2+1}}}{x^2+1}=\frac{1}{(x^2+1)^{3/2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.