Answer
$\frac{1}{(x^2+1)^{3/2}}$
Work Step by Step
1. $\sqrt {x^2+1}-x\cdot\frac{2x}{2\sqrt {x^2+1}}=\frac{2(x^2+1)-2x^2}{2\sqrt {x^2+1}}=\frac{1}{\sqrt {x^2+1}}$
2. $\frac{\sqrt {x^2+1}-x\cdot\frac{2x}{2\sqrt {x^2+1}}}{x^2+1}=\frac{1}{(x^2+1)^{3/2}}$