Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 66

Answer

$ \frac{9}{4}$

Work Step by Step

$(\frac{8}{27})^{-2/3}=(\frac{27}{8})^{2/3}=(\frac{3^3}{2^3})^{2/3}=(\frac{3}{2})^{2}=\frac{9}{4}$
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