Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 48

Answer

$ \frac{\sqrt {14}-2\sqrt 2}{3}$

Work Step by Step

$\frac{\sqrt 2}{\sqrt 7+2}=\frac{\sqrt 2}{\sqrt 7+2}\times\frac{\sqrt 7-2}{\sqrt 7-2}=\frac{\sqrt 2(\sqrt 7-2)}{7-4}=\frac{\sqrt {14}-2\sqrt 2}{3}$
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