Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 45



Work Step by Step

We rationalize the denominator by multiplying both numerator and denominator by $\sqrt 5$: $$ \frac{-\sqrt 3}{\sqrt 5}=\frac{-\sqrt 3\sqrt 5}{\sqrt 5 \sqrt 5}=\frac{-\sqrt{15}}{5} $$
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