Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 72

Answer

$ \frac{y^{1/2}}{x^{1/4}}$

Work Step by Step

$\frac{(xy)^{1/4}(x^2y^2)^{1/2}}{(x^2y)^{3/4}}=[\frac{xyx^4y^4}{x^6y^3}]^{1/4}=[\frac{y^2}{x}]^{1/4}=\frac{y^{1/2}}{x^{1/4}}$
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