#### Answer

$\color{blue}{11x^2-x+2}$

#### Work Step by Step

Distribute $3x$ to obtain:
$=x^2-3x+2-(x-4x^2)+3x(2x)+3x(1)
\\=x^2-3x+2-(x-4x^2)+6x^2+3x$
Subtract each term of the binomial:
$=x^3-3x+2-x-(-4x^2)+6x^2+3x
\\=x^2-3x+2-x+4x^2+6x^2+3x$
Combine like terms to obtain:
$=(x^2+4x^2+6x^2)+(-3x-x+3x)+2
\\=11x^2+(-x)+2
\\=\color{blue}{11x^2-x+2}$