Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test - Page 85: 14


The poverty threshold in 2012 was around $\color{blue}{\$11,727}$.

Work Step by Step

Since $x=0$ corresponds to 1999 and $x=1$ corresponds to 2000, then $x=13$ corresponds to 2012. Substitute $13$ to $x$ to obtain: $y=2.719(13^2)+196.1(13)+8718 \\y=2.719(169)+2549.3+8718 \\y= 459.511+ 2549.3+8718 \\y=11726.811$ Thus, the poverty threshold in 2012 was around $\color{blue}{\$11,727}$.
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