## Precalculus (6th Edition)

$B \cap C$ is the set that contains elements common to sets B and C. Notice that the only element common to sets B and C is $1$. Thus, $B\cap C=\left\{1\right\}$ $(B\cap C \cup D$ contains the combined elements of $(B\cap C)$ and $D$. Since the element of $D$ is $4$, then $\color{blue}{(B\cap C \cup D=\left\{1, 4\right\}}$ Therefore, the given statement is false.