## Precalculus (6th Edition)

$(A' \cup C) \cap B'=\color{blue}{\left\{6, 7, 8\right\}}$
$A'$ is the set that contains the element/s of the universal set $U$ that are not elements of $A$. Thus, $A' = \left\{7, 8\right\}$ $A' \cup C$ is the set that contains the combined elements of $A'$ nd $C$. Thus, $A'\cup C=\left\{1, 6, 7, 8\right\}$ $B'$ is the set that contains the elements of the universal set $U$ that are not elements of $B$. Thus, $B' = \left\{2, 4, 6, 7, 8\right\}$ $(A' \cup C) \cap B'$ is the set the contains elements that are common to both $(A' \cup C)$ and $B'$. Note that the elements common to both sets are: 6, 7, 8 Therefore, $(A' \cup C) \cap B'=\color{blue}{\left\{6, 7, 8\right\}}$