## Precalculus (6th Edition)

$\color{blue}{-4}$
Substitute the given values of the variables to obtain: $=\left|\dfrac{(-2)^2+2(-4)(5)}{3(-2+5)}\right| \\=\dfrac{4+(-40)}{3(3)} \\=\dfrac{-36}{9}$ Simplify the fraction by cancelling out the common factors to obtain: $\require{cancel} \\=\dfrac{\cancel{-36}(-4)}{\cancel{(9)}} \\=\color{blue}{-4}$