Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test - Page 85: 13


The poverty threshold in 2005 was around $\color{blue}{\$9,992}$.

Work Step by Step

Since $x=0$ corresponds to 1999 and $x=1$ corresponds to 2000, then $x=6$ corresponds to 2005. Substitute $6$ to $x$ to obtain: $y=2.719(6^2)+196.1(6)+8718 \\y=2.719(36)+1176.6+8718 \\y=97.884 + 1176.6+8718 \\y=9992.484$ Thus, the poverty threshold in 2005 was around $\color{blue}{\$9,992}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.