Answer
$\color{blue}{1}$
Work Step by Step
$\require{cancel}
\\=\dfrac{(p-4)(p+3)}{(p-5)(p+3)} \cdot \dfrac{(p-5)(p-4)}{(p-4)(p-4)}
\\=\dfrac{\cancel{(p-4)}\cancel{(p+3)}}{\cancel{(p-5)}\cancel{(p+3)}} \cdot \dfrac{\cancel{(p-5)}\cancel{(p-4)}}{\cancel{(p-4)}\cancel{(p-4)}}
\\=\color{blue}{1}$
