Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 53: 30

Answer

$\color{blue}{\dfrac{2y+1}{y+1}}$

Work Step by Step

Factor the numerator and the denominator then cancel the common factors to obtain: $\require{cancel} =\dfrac{(3y+4)(2y+1)}{(3y+4)(y+1)} \\=\dfrac{\cancel{(3y+4)}(2y+1)}{\cancel{(3y+4)}(y+1)} \\=\color{blue}{\dfrac{2y+1}{y+1}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.